(2n+3)(6n-1)=15n^2-(3n-2)(n-2)

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Solution for (2n+3)(6n-1)=15n^2-(3n-2)(n-2) equation: 



(2n+3)(6n-1)=15n^2-(3n-2)(n-2)

We move all terms to the left:

(2n+3)(6n-1)-(15n^2-(3n-2)(n-2))=0

We multiply parentheses ..

(+12n^2-2n+18n-3)-(15n^2-(3n-2)(n-2))=0



We calculate terms in parentheses: -(15n^2-(3n-2)(n-2)), so:

15n^2-(3n-2)(n-2)

We multiply parentheses ..

15n^2-(+3n^2-6n-2n+4)

We get rid of parentheses

15n^2-3n^2+6n+2n-4

We add all the numbers together, and all the variables

12n^2+8n-4

Back to the equation:

-(12n^2+8n-4)



We get rid of parentheses

12n^2-12n^2-2n+18n-8n-3+4=0

We add all the numbers together, and all the variables

8n+1=0

We move all terms containing n to the left, all other terms to the right

8n=-1

n=-1/8

n=-1/8

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